today we didn't have a formal lab, however prof Mason did show us how to determine the power that delivered by AC source.
Following picture is handsome Prof Mason looking into the bulbs.
Following picture shows the peak of AC source is equal to the DC source, in this case the bulb powered by AC source is dimmer than the bulb powered by DC source.
following picture shows that when the two bulbs are equally bight, the Peak voltage of AC source is about 1.44 which is roughly square root of 2 times the voltage of DC source,
The experiment is really helpful since it visualize the effect of power delivered by different sources.
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